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Power Lines: Getting The Proper Flow
More factors that affect power transfer between
an amplifier and transducer
By
Pat Brown

As detailed in my previous articles on power issues (Live Sound February
and March 2003), there are a number of possibilities for rating a power
source. The most straightforward is a simple rating for continuous available
power, a product of the maximum voltage (pressure) output times the maximum
available current (flow) from the amplifier. This “Volt-Ampere” rating
represents the largest number that could be used to characterize the amplifier.
For the “ideal” amplifier, we could simply multiply the DC rail voltage
times the maximum current available from the power supply into a purely
resistive load. Unfortunately, the only value of such a rating would be
its affect on retail sales. This large number must be de-rated in light
of the actual conditions under which amplifiers must operate. So what
factors serve to reduce the “ideal” output power?
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Figure 1: A sine wave plotted as a function of time.
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First, no sound reinforcement amplifier is called upon to deliver
DC voltage and current into a load. If such a signal were indeed
applied to a loudspeaker, it would quickly (and silently) burn up!
Loudspeakers only vibrate with the application of alternating current,
or AC. We could pulse the DC current, producing a square wave, but
this still would bear little resemblance to a real-world audio waveform.
Most amplifiers are rated based on their ability to pass a sinusoidal
waveform.
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The sine wave, when applied to a loudspeaker, makes it move in and out
like a piston. Sine waves are discrete in their spectral content, meaning
that they contain only one frequency. They are also the building blocks
of more complex waveforms. Since the typical sound system must pass many
thousands of frequencies, it would take a lot of sine wave testing to
fully characterize an amplifier! One possibility is to rate the amplifier
using a 1 kHz sine wave, and then add an additional descriptor for how
much this will vary over the bandwidth of the amplifier.
A power bandwidth of -3 dB would mean that the guaranteed power output
of the amplifier is one-half of the 1 kHz rating. That seems like a big
difference, but it’s not when you consider the logarithmic characteristics
of human hearing. One-half power is just noticeably lower in sound level.
So let’s go with the sine wave for rating the amplifier. A 500-watt continuous
amplifier will deliver 500 watts to my loudspeaker, right? Well, only
if you play sine waves through it! In reality, the power flow will be
much lower. This is due to the complex nature of the audio waveforms generated
by real-world program sources.
The waveforms produced by a drum kit or lead singer bear little resemblance
to sine waves. They are inherently more complex. Before we take this thought
further, let’s look at some characteristics that describe time-varying
voltages.
IT’S ABOUT TIME
Figure 1 shows a sine wave plotted as a function of time. This statement
means that the amplitude (vertical displacement) of the voltage is time-dependent.
Like the stock market and the air temperature, the question of “how much?”
depends on “when?” So what value do we assign to the voltage and, ultimately,
the power generated by the sine wave? One possibility is to use the maximum
displacement from zero. This is the peak voltage of the waveform, and
it represents the largest value that we could give it. Unfortunately,
the peak voltage has little to do with loudness or power.
Earlier we showed that power generation is a time-dependent parameter.
A peak can have high amplitude but not last long enough to produce much
power flow. Power is ultimately tied to the root-mean-square (RMS) value
of the waveform. The RMS voltage can be thought of as the “area under
the curve” described by the waveform. It is numerically equivalent to
the DC voltage that would generate the same heat for the specified time
interval. This “heating value” is what must be considered to assess power
flow and loudness.
RMS voltage is determined by squaring all amplitude values (this makes
them positive), and then taking the square root of the mean (average)
value. Power is then calculated by squaring the RMS voltage and dividing
by the resistance of the load, the result being termed “continuous average
power” or just “continuous” for short. For a sine wave (and a sine wave
only), the RMS voltage is 0.707 times the peak voltage. This means that
a sine wave will generate one-half of the power that the DC rail voltage
would for the same time span.
Using the “hypothetical” DC rating as a reference, we would say that the
sine wave has a “crest factor” of 3 dB. So, an amplifier with a sine wave
rating of 500 watts continuous could be rated at 1000 watts “peak” output.
So why not rate it at 1000 watts?
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Figure 2: A lower RMS voltage means a higher crest factor, which
in turn means less power delivered to the load.
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There are several reasons, including the fact that most amplifiers
cannot sustain such an output power for any appreciable time period.
It is also unlikely that any real-world audio waveform would stay
at the peak voltage for any appreciable time span. So, when you
bring “time” into it, peak values become less meaningful. And since
power is the “rate of doing work”, it is impossible to consider
power independent of time. Also, just like passing your finger quickly
through the flame of a candle, loudspeakers and amplifiers can be
given very large heat generation and dissipation ratings if the
time element approaches zero.
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ROOM AT THE TOP
Real-world audio waveforms have much lower RMS values (less area under
the curve) than sine waves do, even though their peak values may be the
same (see Figure 2). A lower RMS voltage means a higher crest factor,
which in turn means less power delivered to the load. One way to determine
how much power a complex waveform will generate is to use the peak power
output based on the DC rail voltage as a reference, and then subtract
the crest factor of the complex waveform from it. This will yield the
power generated by the complex waveform.
For example, an amplifier rated at 500 watts continuous average power
with a sine wave will have a theoretical peak output power 3 dB higher
(the crest factor of the sine wave) - 1,000 watts in this case. Using
this as a reference (that’s all it’s good for), we can subtract the crest
factor of the real-world waveform. Refer to the following chart for some
common decibel relationships:
0 dB - reference value
-3 dB - one-half power
-6 dB - one-fourth power
-10 dB - one-tenth power
-20 dB - one-one-hundredth power
These numbers will be useful for determining how much power a waveform
generates based on its crest factor. Our 1,000-watt “theoretical” amplifier
would only generate 500 watts for a sine wave signal (-3 dB), 250 watts
for a 6 dB crest factor signal (highly compressed music or speech), 100
watts for a 10 dB crest factor signal (slightly compressed music or speech),
and only one watt for a 20 dB crest factor signal (“raw” music or speech).
So, in the real world of live performances, a 500-watt “sine wave rated”
amplifier is likely to deliver only a fraction of this power to the loudspeaker.
The implications? First, if a loudspeaker can safely dissipate 100 watts
continuous average power (based on destructive testing - sounds like fun,
doesn’t it?), then the required amplifier size to deliver 100 watts will
be considerably higher. This is because the amplifier is rated using a
sine wave, which yields a much higher power output than a real-world audio
waveform. Assuming a crest factor of 10 dB, the amplifier would have to
have a peak rating of 1,000 watts (sine rating of 500 watts) to actually
deliver 100 watts into a resistive load. This “extra” room is called “headroom”.
This is why it is common practice to oversize the amplifier relative to
the loudspeaker’s power rating.
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Figure 3: A meter that can display the peak and RMS voltage of the
waveform at the same time.
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But if you connect a 500-watt amplifier to this loudspeaker, and
someone feeds it a low crest factor signal (like a sine wave), it
is likely that the loudspeaker would burn up since its power rating
has been exceeded.
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So, we want a large amplifier to provide sufficient headroom for high
crest factor signals, but we need to make sure that a low crest factor
signal is not applied that will burn up the loudspeaker. Catch 22. No
free lunch. It depends. There is no escaping these realities in the real
world of live performance.
Let’s sum it up with some guidelines. The sensitivity rating of a loudspeaker
specifies a sound pressure level that will exist at a one meter distance
when one watt of electrical power is applied to the loudspeaker’s terminals
(2.83 VRMS across eight ohms). In other words, if you put one watt in,
it will be this loud at this distance. The amplifier size that is required
to deliver one watt is dependent on the crest factor of the program material.
Using 10 dB as a rule-of-thumb, the required peak power rating would be
10 watts. So, it takes 10 watts peak to get one watt continuous! If we
scale these numbers up to a loudspeaker rated to dissipate 100 watts continuous,
the peak amplifier rating would be 1000 watts. Given that amplifiers are
typically rated with sine waves, the continuous power rating of the amplifier
would be one-half the peak rating, or 500 watts. Therefore, it takes a
500-watt sine wave rated amplifier to deliver 100 watts to a loudspeaker
if the program material has a 10 dB crest factor. How’s that for confusing?
CREST FACTOR AWARENESS
So, how do I determine the crest factor of my program material? After
all, this is what ultimately determines the required power rating of the
amplifier and the power flow into the loudspeaker. There are two ways
to approach this. For recordings, the crest factor can be calculated quickly
and accurately using a wave editor program. Open the wave file, select
a time span, and look for a menu selection called “statistics” or something
similar. This should display the crest factor for the time span selected.
For live music, it’s a bit harder. You need a meter that can display the
peak and RMS voltage of the waveform simultaneously (see Figure 3). On
such a meter, the crest factor can be monitored in real-time - VERY cool.
If the meter is calibrated so that its highest peak indication is the
clipping point of the system (this is the right way to do it), then the
lower (RMS) indication on the meter will correlate with how much power
is being generated. This allows the operator to turn the system down if
the RMS gets too high (which is also the right way to do it).
The third way is to use some rules-of-thumb for typical crest factors.
Once you factor in all of the variables (I won’t do it here), the crest
factors in live performance are often in the 6 to 10 dB range for mid
and high frequencies. They tend to be lower at low frequencies where synth
and bass guitar signals look more like sine waves. This means that at
mid and high frequencies you will be using one-fourth to one-tenth of
the peak rating of the amplifier. At low frequencies you will be using
up to one-half of the peak rating of the amplifier.
If you are a disciplined sound operator, you can oversize your amplifiers
by this much (relative to the loudspeaker’s rating) and probably not get
into trouble. The safest overall approach is to use large amplifiers,
but then monitor the program’s RMS and peak levels to stay within the
loudspeaker’s limitations. Also remember that compressors and limiters
reduce the crest factor of the signal, which means that more power is
delivered to the load. Again, real-time monitoring will tell the story.
THE CONCLUSION?
The bottom line is that there are many variables that determine the power
flow from amplifier to loudspeaker. An understanding of these basics can
allow us to stay within the operating limits of our hardware. Power ratings
are meaningless when there is smoke coming out of the loudspeakers.
This series of articles hasn’t attempted to present a black-and-white
recipe for amplifier/loudspeaker selection. What it has done is put the
variables on the table that the system designer must consider when selecting
components. There’s a lot to think about, and there WILL be a test.
Editor’s Note: The test Mr. Brown refers to will be included in
Live Sound’s May 2003 issue, so start studying!
Pat Brown, with his wife, Brenda, heads up Syn-Aud-Con, leading audio
training sessions around the world. For more info, go to www.synaudcon.com
April 2003 Live Sound International
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